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0.0025x^2-800x+800=0
a = 0.0025; b = -800; c = +800;
Δ = b2-4ac
Δ = -8002-4·0.0025·800
Δ = 639992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{639992}=\sqrt{4*159998}=\sqrt{4}*\sqrt{159998}=2\sqrt{159998}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-800)-2\sqrt{159998}}{2*0.0025}=\frac{800-2\sqrt{159998}}{0.005} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-800)+2\sqrt{159998}}{2*0.0025}=\frac{800+2\sqrt{159998}}{0.005} $
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